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發(fā)表于 2009-4-12 10:49:43
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Can I convert points of a plane into individual points w1 _5 p s. D) I0 s$ K; X
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我能從多點(diǎn)組成的面中分離出單獨(dú)的點(diǎn)嗎?
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I'm sorry, I have not played around to find out for myself due to work load but, I have a disc with 20 pockets, each pocket has 3 recesses. I need to check
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the "Z" distance between 2 planes and since I need to referance / align each plane later in the PPG, it would be much easier to pull 1, 5 points out from the , ] P% P, F8 ~- c$ k
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plane and call it an individual point to get my "Z" distance. I can not due a loop due to each point and plane needs a seperate name and for the scientists
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* X/ v% P. d8 S$ a! Mto be able to figure out the CMM output easily and at the bottom of each pocket I take 25 pt's so tghey can determin contour of each pocket.: F$ ]2 O' K; B+ s3 D
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對(duì)不起,我不是為了好玩而是真的工作需要,我有一個(gè)圓盤(pán)工件,上面分布20個(gè)輪廓,每個(gè)輪廓有3個(gè)凸行。 我需要檢查兩個(gè)面之間的z軸距離.在工件坐標(biāo)系中需要整理每一個(gè)面,
5 V! D h/ D; C# H6 C3 ?+ v這將很容易將 1, 5 點(diǎn)分離出,同時(shí)調(diào)出一個(gè)單獨(dú)的點(diǎn)坐標(biāo)就可以得到我的z軸距離.我不能得到一個(gè)循環(huán)是因?yàn)槊恳粋€(gè)點(diǎn)和面都需要一個(gè)獨(dú)立的名字.為了cmm更容易的輸出科學(xué)的計(jì)5 r- W D8 @" Q5 t7 W
9 q8 p. g" i9 s v: D$ ^& {算值.在每個(gè)孔的地步我取了25個(gè)點(diǎn)以描述每個(gè)圓輪廓; p6 [8 w Z F; R
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why don't you measure as points, then you can connect the sets of points together as planes, but you will still have the points to do any further analysis
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, h2 B! E% `5 A: l為什么你不測(cè)量點(diǎn)要素,然后你可以將點(diǎn)云組合成平面,同時(shí)你依然擁有點(diǎn)要素做進(jìn)一步的分析
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Thanks for the input, I've done that before but just thought I could grab a point of a plane rather than having to manually take my plane points.
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1 n" H9 y c7 V8 _謝謝回復(fù),我已經(jīng)那樣做了, 但是我想能不能從平面上抓一點(diǎn),而不是想手動(dòng)的測(cè)量平面點(diǎn).
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- X; Y, i* T2 |( d' k! g, R2 qIf you have measured the plane(s) as auto planes, then you can get hold of the individual measured points using the formula calculation tokens2 _ M- d2 L0 R7 {% g0 E F" F
- for example 'PL[1].MP[1].X' would return the value in X of the first point in plane memory 1. So you could just process a simple loop after the measurement 5 s* R% u% @* z7 u
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of each plane to grab hold of the X,Y & Z vals of each point and transfer them into individual element points.
/ d) h$ m/ [. f9 Z' N( c8 HBe aware that the points are uncompensated. I have attempted to attach the example prog (.CAB and ._PI files) which you can import from the part manager, R. V" A3 |* z; J
Click here for plane points._PI 7 C! S; S, ?/ M+ Q. m. b
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如果你已經(jīng)測(cè)量平面為自動(dòng)平面,那么你能得到一個(gè)單獨(dú)的點(diǎn)通過(guò)變量計(jì)算
5 I4 I5 [ N% z9 I- J* N- 舉例來(lái)說(shuō) 'PL[1].MP[1].X'將會(huì)返回平面第一個(gè)點(diǎn)的x軸坐標(biāo)值. 因此你僅僅需要做一個(gè)簡(jiǎn)單的循環(huán)從每一個(gè)面的測(cè)量結(jié)果中分離出它每一個(gè)點(diǎn)的xyz坐標(biāo)值.然后把他們組合成
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一個(gè)個(gè)單獨(dú)的點(diǎn)要素
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( ]5 o4 N# w5 Y$ c% I! Y' ^注意,這些點(diǎn)是沒(méi)有探針補(bǔ)償。 我已經(jīng)嘗試附上一個(gè)程序例子(.CAB and ._PI files),你可以從程序入口導(dǎo)入/ v( y0 e. X5 M y0 p$ [9 ~+ J
點(diǎn)擊這里為了平面點(diǎn)。_PI
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flyfish - send me your email and I will send the program to you
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When you grab the points in formula calculation, you should be able to
4 k" f; N* z( Ualso deduct the probe radius result to equate to a compensaed point.
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$ Z! ?6 U) [3 J6 dObviously only if you probed perpendicular to the surface. . . I think .
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% ^" x/ ^. ]( R" f. }/ R% B當(dāng)你抓取測(cè)量點(diǎn)的時(shí)候,你同樣能夠到也減去探針半徑值得到一個(gè)無(wú)補(bǔ)償點(diǎn)。8 X# l9 k, O+ w- C
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當(dāng)然如果你的探針運(yùn)動(dòng)軌跡垂直與工件表面... 我個(gè)人看法。 |
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